2023-11-29
Theorem 1: Central Limit Theorem (CLT)
Let \(X_i\) be iid rv’s with common mean \(\mu\) and variance \(\sigma^2\), for \(i=1,2,\ldots,n\). Then \[\sum_{i=1}^n X_i \rightarrow \text{N}(n\mu, n\sigma^2)\]
Corollary 1
Let \(X_i\) be iid rv’s with common mean \(\mu\) and variance \(\sigma^2\), for \(i=1,2,\ldots,n\). Then \[\bar{X}=\frac{\sum_{i=1}^n X_i}{n} \rightarrow \text{N}\Bigg(\mu, \dfrac{\sigma^2}{n}\Bigg)\]
Example 1
According to a large US study, the mean resting heart rate of adult women is about 74 beats per minutes (bpm), with standard deviation 13 bpm (NHANES 2003-2004).
Find the probability that the average resting heart rate for a random sample of 36 adult women is more than 3 bpm away from the mean.
Repeat the previous question for a single adult woman.
Example 2
Let \(X_i \sim Exp(\lambda)\) be iid RVs for \(i=1,2,\ldots,n\). Then \[\sum_{i=1}^n X_i \rightarrow\]
Binomial rv’s: Let \(X \sim Bin(n,p)\)
Poisson rv’s: Let \(X \sim Poisson(\lambda)\)
Example 3
Suppose that the probability of developing a specific type of breast cancer in women aged 40-49 is 0.001. Assume the occurrences of cancer are independent. Suppose you have data from a random sample of 20,000 women aged 40-49.
How many of the 20,000 women would you expect to develop this type of breast cancer, and what is the standard deviation?
Find the exact probability that more than 15 of the 20,000 women will develop this type of breast cancer.
Use the CLT to find the approximate probability that more than 15 of the 20,000 women will develop this type of breast cancer.
Use the CLT to approximate the following probabilities, where \(X\) is the number of women that will develop this type of breast cancer.
\(\mathbb{P}(15 \leq X \leq 22)\)
\(\mathbb{P}(X > 20)\)
\(\mathbb{P}(X < 20)\)
Find the approximate probability that more than 15 of the 20,000 women will develop this type of breast cancer - not using the CLT!
Use the CLT to approximate the approximate probability in the previous question!
Chapter 37 Slides